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36x^2+85x+10=0
a = 36; b = 85; c = +10;
Δ = b2-4ac
Δ = 852-4·36·10
Δ = 5785
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(85)-\sqrt{5785}}{2*36}=\frac{-85-\sqrt{5785}}{72} $$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(85)+\sqrt{5785}}{2*36}=\frac{-85+\sqrt{5785}}{72} $
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